AN INTRODUCTION TO
NEWTONIAN MECHANICS by Edward Kluk Dickinson State University, Dickinson ND |
HORIZONTAL PROJECTILE MOTION
A
technical introduction
This applet simulates all kinds of
projectile motion with low gravity acceleration and makes
possible to time these motions. A motion can start from eleven
marked heights at the distance 0 m. Its initial speed and
direction are selectable from three labelled choice boxes. If
default sign "+" is selected, a selected projection
angle counts counter clockwise from a dotted horizontal line.
Otherwise it counts clockwise. Every time the red object reaches
the edge of the vision field it stops and Reset button is
activated. This button let us restore initial conditions for the
last motion. The clear button restores default initial conditions
for the motion and repaints the vision field. Finally, if the
path tracer is on, a path of the object is drawn in the vision
field.
If you switch to another page,
minimize the browser ,or scroll this page losing the vision field
(or part of it) from the screen and later come back to this
applet, the vision field (or part of it) will be lost. To create
an empty vision field click on the reset button(if it is active)
and clear button, or just the clear button if the reset button is
not active. Thus, if you want to make several
"experiments" and compare them, please do not loose the
view of this applet from the screen.
The vision field is also lost if
the page is reloaded. Reloading may even cause an unwanted start
if the applet was reset. Clicking the clear button or, the reset
and clear buttons after unwanted run is finished restores a
normal functionality of this applet.
How vertical and horizontal motions add
We already know mathematical models
for free fall and undisturbed motion on a frictionless and
impenetrable horizontal plane which eliminates a gravitational
pull . A natural question arises what will happen if a body
starts with nonzero horizontal speed without a support of the
horizontal impenetrable plane. A simple experiment with a body
sliding with some horizontal speed off a table shows the body
motion as a combination of vertical and horizontal motions. As we
already know an accurate timing of this kind of motion is not
possible without high tech devices like a fast photography. Some
camcorders have fixed time between consecutive frames and they
can be used to study this kind of motion. But even with such
camcorder our experiment would be complicated.
It is much simpler to go back to our
fictitious planet with the very low gravity acceleration
simulated in the applet. Start it with all default settings
except of speed which should be set at 0.20 m/s. This will
simulate a case of the motion of our current interest. Measure
all time intervals the moving object needs to reach each
consecutive vertical dotted line from its starting point. These
consecutive dotted lines are in a distance of 1 m from each
other. Therefore in the first measured time interval the object
covers 1 m in horizontal direction , in the second
interval 2 m, and so for. A total distance covered by the object
for each interval is greater than that because it moves
simultaneously in both horizontal and vertical directions.
Graphing horizontal distance versus time you will get exactly the
same result as for the motion along a horizontal frictionless
plane. Namely, the horizontal component of object's speed vH
remains constant because your graph is a straight line. The slope
of this line represents the mentioned above horizontal component
of the speed. Let us introduce a two dimensional Cartesian frame
of reference with an origin at zero height and zero displacement
which is in the lower left corner of the vision field, x
axis directed horizontally to the right and y axis
directed vertically up. Then, you should be able to conclude from
your graph that the elapsed time t and x
coordinate of the object in the Cartesian reference frame are
related by the following formula
x = vH t ,
representing a uniform
motion (motion with a constant speed and no change of
direction) along x axis.
Now it is time to collect next set of
data related to change of object's vertical position. Measure all
time intervals the moving object needs to reach each consecutive
horizontal dotted line from its starting point. These consecutive
dotted lines are also in a distance of 1 m from each other.
Relying on your experience with a free fall motion you may expect
that a covered vertical distance d may be
proportional to t 2 rather
than t. Graph d versus t 2
looking for "experimental" confirmation of this
hypothesis. Your results including value of acceleration should
be practically identical like for the free fall case. After all
you are on the same low gravity acceleration planet. Therefore
d = a t 2 / 2
where the acceleration a should be about 0.01
m / s 2.
Math helps to reach more conclusions
The vertical distance d
covered by the falling object is related to its y
coordinate. If an initial y coordinate is denoted
as yo then
y = yo - d = yo
- a t 2 / 2 .
Mathematical forms of x and y as
functions of time deduced from our "experimental"
results show that the motion of the object is composed of two
independent simple motions. The horizontal motion with a constant
speed vH and vertical free
fall with a constant acceleration a. They are
independent in this sense that a modification of the horizontal
motion by changing its initial speed vH
does not influence the vertical motion and a modification of the
vertical motion by changing its acceleration does not influence
the horizontal motion. To check "experimentally" the
first of these two properties of this kind of motion, make timing
for a vertical component of motions with initial horizontal
speeds 0.1 m / s and 0.15 m / s. If
horizontal and vertical components of these motions are
independent then the vertical timings for both selected
motions should be the same within of an experimental accuracy.
You should be aware that if an air resistance plays an important
role the horizontal and vertical components of motion are not
independent anymore.
Calculating t from the
formula for x and substituting the result to the
formula for y gives the following result
y = yo - a (x / vH
) 2 / 2 = yo - a /(2 vH2
) x 2
In the defined above Cartesian reference frame this relation
formally describes a parabola with opening down and vertex at x
= 0 and y = yo.
The upper part of the right branch of this parabola describes the
path of the object. To visualize it, run the applet with
the path tracer on and other parameters as defaults. Surprisingly
enough, Galileo knew that paths for this kinds of motion
are parabolic. Now insert into the parabola equation for yo
and vH their default
values 10 m and 0.25 m / s
. Select a few simple values for x and
calculate respective y values comparing them with
values for the same x values along the trace left
by the object. If our mathematical model of horizontal projectile
motion is correct the calculated and "experimental" y
values should be in a good agreement.
Evaluation
If at this point you do understand:
the objectives of this lesson are fully achieved. If you have doubts try to read it once more concentrating on them, but do not try to memorize this text. physics is not about memorizing, it is about understanding.
Since February 1997 you are visitor
Last update: Jan 10, 1997 | E - mail to Edward Kluk |
Copyright (c) 1996 Edward Kluk |